Fraction of an Amount Year 6 Fractions Learning Video Clip

Step 15: Fraction of an Amount Year 6 Fractions Learning Video Clip

Roman, Rae and Trig need two final keys so as they can escape. They must solve fraction of amount puzzles and problems to gain one of the keys.

More resources for Autumn Block 3 Step 15.

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Discussion points for teachers

1. How much time do the group have left?
Discuss if the fraction is in its simplest form. If not, how can you simplify it? Discuss the strategy for finding fractions of amounts. How will you know when you have the final answer?
12/14 = 6/7  of 1,120 = 960 minutes used. 1,120 – 960 = 160 minutes left.

2. Find the value of the shaded part.
Discuss how the bar model can help. What does the bar model represent?
4/6  of 2,796 = 1,864ml – Container I should be poured.

3. Solve the calculation and choose the matching container of liquid.
Discuss which containers of liquid it cannot be and why
21/28 = 3/4  of 1,768 = 1,326 1,768 – 1,326 = 442 stickers left. Container G should be poured.

4. Match the answers to the calculations. Find the odd answer out.
Discuss working systematically through the calculations. How will you keep track of which answers have and have not been used?
16/40 = 3/4  of 985 = 394 20/36 = 5/9  of 693 = 385 18/48 = 3/8  of 992 = 372 so the odd answer out = 361ml – Container D should be poured.

5. Solve the calculation. Pour in two containers which total the answer.
Discuss the key information from the question.  This question is open-ended for the children to discuss.
14/35 = 2/5  of 2,685 = 1,074ml       The containers could be 394ml + 680ml (E + F) , 372ml + 702ml (B + H)  or 385ml + 689ml (A + C).

National Curriculum Objectives

Mathematics Year 6: (6F6) Associate a fraction with division and calculate decimal fraction equivalents [for example, 0.375] for a simple fraction [for example, 3/8]

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